49x^2=-14x+8

Solution for 49x^2=-14x+8 equation:

49x^2=-14x+8

We move all terms to the left:

49x^2-(-14x+8)=0

We get rid of parentheses

49x^2+14x-8=0

a = 49; b = 14; c = -8;
Δ = b2-4ac
Δ = 142-4·49·(-8)
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1764}=42$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-42}{2*49}=\frac{-56}{98}
=-4/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+42}{2*49}=\frac{28}{98}
=2/7
$